## Problems on Trains MCQs

The answers of questions marked with * are subject to change with time

Last Updated: 20 Jan 2022

**A train with a speed of 60 km/hr crosses a pole in 9 secs. What is the length of the train?**

A. 120 m**B. 150 m**

C. 325 m

D. 180 m

**Labour Inspector-19**

Speed of the train = 60 km/hr = 60 x (5/18) m/s

Time taken = 9 s

The distance travelled by the train will be its length.

Distance = Speed x Time

Length of the train = 60 x (5/18) x 9 = 150 m

**Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:**

A. 9 s

B. 9.6 s**C. 10.8 s**

D. 10 s

**Tax Inspector-18 (Guj)**

Relative speed = (60+40) km/hr = 100 x (5/18) m/s = 250/9 m/s

Distance covered in crossing each other = (140+160) m = 300 m

Time = Distance / Speed

Time = 300 x (9/250) = 10.8 s

**Two trains are running in opposite direction with the speed of 62 km/h and 40 km/h respectively. If the length of one train is 250 m and they cross each other in 18 seconds, the length of the other train is:**

A. 145 m

B. 230 m**C. 260 m**

D. 360 m

**Asst Livestock-20/Asst Special Education Dept-20**

Time = 18 s

Relative speed = (62+40) km/hr = 102 x (5/18) m/s = 85/3 m/s

Length of first train = 250 m

Length of second train = L

Time = Distance / Speed

18 = (250+L) / (85/3)

3(250+L) / 85 = 18

250+L = (18×85) / 3

250+L = 510

L = 260 m

**A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?**

A. 69.5 km/h

B. 70 km/h**C. 79.2 km/h**

D. 79 km/h

**Asst Punjab Workers Welfare Board LHRD-19**

Length of the bridge = 264 m

Time taken to pass the bridge = 20 s

Time taken to pass the post = 8 s

Length of the train = X

To pass the bridge, train need to cover Train’s length + Bridge’s length (X+264)

Speed = Distance / Time

X/8 = (264+X) / 20

20X = 264×8 + 8X

20X – 8X = 264×8

12X = 2112

X = 2112 / 12

X = 176 m

Speed of the train = 176 / 8 = 22 m/s

Converting into km/h

22 x (18/5) = 79.2 km/h

**Three men start together to travel the same way around a circular track of 11 km. Their speeds are 4, 5.5 and 8 km/h respectively. When will they meet at the starting point for the first time?**

A. after 11 hours

B. after 21 hours**C. after 22 hours**

D. after 33 hours

**AD (I) FIA-19**

Time for one revolution by each of man = 11/5, 11/(11/2), 11/8

= 11/5, 2/1, 11/8

Taking L.C.M of 11/5, 2/1, 11/8

= 22 hr

Hence, they will meet at starting point after 22 hr.

**In a 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this A beats B by:**

A. 24 m**B. 20 m**

C. 28 m

D. 30 m

**Zilladar-20**

Distance covered by B in 9 s

= (100/45) x 9 = 20 m

∴ A beats B by 20 m

**In covering a distance of 30 km, Abdul takes 2 hours more than Basit. If Abdul doubles his speed then he would take 1 hour less than Basit. What is the speed of Abdul?**

A. 15 km/hr

B. 8 km/hr**C. 5 km/hr**

D. 10 km/hr

**Labour Officer-17**

Let Abdul’s speed be x km/hr

Then, 30/x – 30/2x = 3

⇒ 6x = 30

⇒ x = 5 km/hr